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4x^2-0.14x-0.014=0
a = 4; b = -0.14; c = -0.014;
Δ = b2-4ac
Δ = -0.142-4·4·(-0.014)
Δ = 0.2436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.14)-\sqrt{0.2436}}{2*4}=\frac{0.14-\sqrt{0.2436}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.14)+\sqrt{0.2436}}{2*4}=\frac{0.14+\sqrt{0.2436}}{8} $
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